Solution Exercice 3 / Série 3

a) Table de vérité :

h1 h2 h3 S1 S2
0 0 0 0 0
0 0 1 0 1
0 1 0 0 1
0 1 1 1 0
1 0 0 0 1
1 0 1 1 0
1 1 0 1 0
1 1 1 X X

Equations algébriques :

        _                _                _
S1= h1.h2.h3+h1.h2.h3+h1.h2.h3

        _  _       _       _       _   _
S2= h1.h2.h3+h1.h2.h3+h1.h2.h3

Tableaux de Karnaught :

S1 :

  \h3
h1h2\

 0 1
00 0 0
01 0 1
11 1 X    
10 0 1

      
S1 = h1h2 + h2h3 +h1h3
S2 :

  \h3
h1h2\

 0 1
00 0 1
01 1 0
11 0 X
10 1 0

        _  _       _       _       _   _
S2= h1.h2.h3+h1.h2.h3+h1.h2.h3

Circuit :

à suivre....