Solution Exercice 6 / Série 3

a) Table de vérité :

p e m c P E M C
0 0 0 0 0 0 0 0
0 0 0 1 0 0 0 0
0 0 1 0 0 0 0 0
0 0 1 1 0 0 0 0
0 1 0 0 0 1 0 0
0 1 0 1 0 0 0 0
0 1 1 0 0 0 0 0
0 1 1 1 0 0 0 0
1 0 0 0 1 0 0 0
1 0 0 1 0 0 0 1
1 0 1 0 0 0 1 0
1 0 1 1 1 0 0 0
1 1 0 0 1 0 0 0
1 1 0 1 1 0 0 0
1 1 1 0 1 0 0 0
1 1 1 1 1 0 0 0

Tableaux de Karnaught :

P :

  \mc
pe \

 00 01 11 10
00 0 0 0 0
01 0 0 0 0
11 1 1 1 1
10 1 0 1 0

                   _ _
P = p.e + p.m.c + p.m.c
E:          _    _ _
E = p.e.m.c
M:              _    _
M = p.e.m.c
C:             _ _
C = p.e.m.c

Circuit :

à suivre....